Answer
Check Prime Number in Java
Java
public class PrimeNumber {
public static void main(String[] args) {
int num = 29;
boolean isPrime = true;
if (num <= 1) {
isPrime = false;
} else {
// Check divisibility from 2 to √num
for (int i = 2; i <= Math.sqrt(num); i++) {
if (num % i == 0) {
isPrime = false;
break;
}
}
}
if (isPrime)
System.out.println(num + " is a Prime number");
else
System.out.println(num + " is NOT a Prime number");
}
}
Output
CODE
29 is a Prime number
Why Check Only Up to √n?
CODE
If n = 36:
Factors: 1×36, 2×18, 3×12, 4×9, 6×6
After √36=6, factors repeat in reverse
So checking 2 to 6 is enough
Print All Primes Up to N (Sieve of Eratosthenes)
Java
public class PrintPrimes {
public static void main(String[] args) {
int n = 50;
System.out.print("Primes up to " + n + ": ");
for (int num = 2; num <= n; num++) {
boolean prime = true;
for (int i = 2; i <= Math.sqrt(num); i++) {
if (num % i == 0) { prime = false; break; }
}
if (prime) System.out.print(num + " ");
}
}
}
Output
CODE
Primes up to 50: 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47
Method as Function (Reusable)
Java
public static boolean isPrime(int n) {
if (n <= 1) return false;
if (n <= 3) return true;
if (n % 2 == 0 || n % 3 == 0) return false;
for (int i = 5; i * i <= n; i += 6) {
if (n % i == 0 || n % (i + 2) == 0) return false;
}
return true;
}
// Usage
System.out.println(isPrime(17)); // true
System.out.println(isPrime(25)); // false
